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Number System

    • Theory
    • Set 1
    • Set 2
    • Set 3
    • Set 4
    • Set 1
    • Set 2
  1. Aptitude
  2. Quantitative
  3. Number System
  4. Theory

Number System: Concepts, Formulas, and Clear Examples

Number system MCQs cover divisibility, remainders, units digits, factors, and base conversions. Modular thinking beats long division.

Learn divisibility tests for 2,3,4,5,8,9,11 and (an mod m)(a^n \bmod m)(anmodm) cycles for units digit.

For remainders when dividing by 9 or 3, digit sum shortcuts often decide the option.

Divisibility tests

  • By 11: alternate digit sum difference divisible by 11.
  • By 8: last three digits divisible by 8.

Remainders

Division algorithm

N=dq+r, 0≤r<dN = dq + r,\ 0 \le r < dN=dq+r, 0≤r<d

Mod addition

(a+b) mod m=[(a mod m)+(b mod m)] mod m(a+b)\bmod m = [(a\bmod m)+(b\bmod m)]\bmod m(a+b)modm=[(amodm)+(bmodm)]modm

Units digit cycles

  • Powers of 2 cycle 2,4,8,6; powers of 3 cycle 3,9,7,1 every 4 exponents mod 4.

Example — Units digit of 7^202

202 mod 4=2202\bmod 4=2202mod4=2. Cycle position 2 for 7 → units digit 9.

Factors and count

Number of factors

N=p1ap2b⋯⇒(a+1)(b+1)⋯N=p_1^{a}p_2^{b}\cdots \Rightarrow (a+1)(b+1)\cdotsN=p1a​p2b​⋯⇒(a+1)(b+1)⋯

LCM/HCF tie-in

  • Product of two numbers = HCF × LCM.
  • Perfect squares have odd factor count.

Base conversion

  • Binary to decimal: sum bit × 2k2^k2k.
  • Decimal to base: repeated divide by base, read remainders up.

Step-by-step method for exam questions

  1. Classify: divisibility, remainder, units digit, or factors.
  2. Apply test or mod cycle; reduce exponent mod cycle length.
  3. For large N mod small d, simplify using digit sum or binomial.
  4. Count factors from prime powers.
  5. Eliminate options failing parity/divisibility.
  6. Select answer.

Formula cheat sheet

SituationFormulaWhen to use
Remainder mod 9Digit sum mod 9Large numbers
Units digit a^nCycle length 4 oftenn large
Factor count(a+1)(b+1)(a+1)(b+1)(a+1)(b+1)Prime power form
Odd factor countPerfect squareRecognition MCQ
Two numbersab=HCF×LCMab=\text{HCF}\times\text{LCM}ab=HCF×LCMMissing one

Frequently asked questions

Negative remainders?

Adjust to 0≤r<m0\le r<m0≤r<m for final answer.

0 mod m?

Means divisible by m.

Last two digits?

Work mod 100; use mod 4 and mod 25 if needed.

Prime check fast?

Trial divide by primes up to n\sqrt{n}n​.

Practice on this platform

Use 4 practice sets (10 MCQs, detailed solution after each answer) and 2 timed mocks (20 minutes) on this topic to convert formulas into speed and accuracy.

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