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Compound Interest

    • Theory
    • Set 1
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    • Set 3
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    • Set 2
  1. Aptitude
  2. Quantitative
  3. Compound Interest
  4. Theory

Compound Interest: Concepts, Formulas, and Clear Examples

CI grows as A=P(1+r)tA = P(1+r)^tA=P(1+r)t where r=R/100r=R/100r=R/100 per compounding period. Each period’s interest earns interest—exponential, not linear like SI.

Watch compounding frequency: half-yearly → rate R/2R/2R/2 per half-year, periods 2T2T2T. Questions often ask CI−SI difference or depreciation (1−r)t(1-r)^t(1−r)t.

Memorize: for 2 years, CI−SI =P(r2)= P(r^2)=P(r2) when annual compounding.

Amount and CI

Annual

A=P(1+R100)TA = P\left(1 + \frac{R}{100}\right)^TA=P(1+100R​)T

CI

CI=A−P\text{CI} = A - PCI=A−P

Example — Two years 10%

P=5000P=5000P=5000, R=10%R=10\%R=10%, T=2T=2T=2. A=5000(1.1)2=6050A=5000(1.1)^2=6050A=5000(1.1)2=6050. CI = 1050. SI = 1000; extra 50 = interest on first year’s 500.

Half-yearly / quarterly

Half-yearly

A=P(1+R/2100)2TA = P\left(1 + \frac{R/2}{100}\right)^{2T}A=P(1+100R/2​)2T

Quarterly

A=P(1+R/4100)4TA = P\left(1 + \frac{R/4}{100}\right)^{4T}A=P(1+100R/4​)4T

CI minus SI

2 years gap

CI−SI=P(R100)2\text{CI} - \text{SI} = P\left(\frac{R}{100}\right)^2CI−SI=P(100R​)2

Depreciation

Value after decay

V=P(1−R100)TV = P\left(1 - \frac{R}{100}\right)^TV=P(1−100R​)T

Doubling time

  • If amount doubles, (1+R/100)T=2(1+R/100)^T = 2(1+R/100)T=2. Solve for RRR or TTT from options.

Effective rate

m periods/year

reff=(1+Rm⋅100)m−1r_{\text{eff}} = \left(1 + \frac{R}{m\cdot100}\right)^m - 1reff​=(1+m⋅100R​)m−1

Step-by-step method for exam questions

  1. Extract P, R, T and compounding type.
  2. Convert to per-period rate and period count.
  3. Compute A=P(1+r)nA=P(1+r)^nA=P(1+r)n.
  4. CI = A − P; compare SI if asked.
  5. Use 2-year difference shortcut when applicable.
  6. Match closest option; watch rounding.

Formula cheat sheet

SituationFormulaWhen to use
Annual CIA=P(1+R/100)TA=P(1+R/100)^TA=P(1+R/100)TDefault annual
Half-yearlyA=P(1+R/2100)2TA=P(1+\frac{R/2}{100})^{2T}A=P(1+100R/2​)2TStated in stem
2-yr CI−SIP(R/100)2P(R/100)^2P(R/100)2Quick gap
DepreciationP(1−R/100)TP(1-R/100)^TP(1−R/100)TValue falls
Double amount(1+R/100)T=2(1+R/100)^T=2(1+R/100)T=2Find R or T

Frequently asked questions

First year CI vs SI?

Same for identical P, R, T=1 year.

Higher compounding frequency?

Higher effective return for same nominal R.

Common trap?

Using SI formula PRT/100PRT/100PRT/100 inside an exponent.

Fractional years?

Align period count (e.g., 18 months half-yearly → 3 periods).

Practice on this platform

Use 4 practice sets (10 MCQs, detailed solution after each answer) and 2 timed mocks (20 minutes) on this topic to convert formulas into speed and accuracy.

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